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AnaGram-Data Structure


An anagram is a rearrangement of the letters in either a word or a phrase (using each letter exactly once in the word or phrase created). Ideally the anagram created relates in some (perhaps humorous) way to the original word or phrase. Such anagrams are described as cognate. The best anagrams are grammatically correct and use techniques such as abbreviating and to 'n' only minimally.

I have Developed an anagram program in VS 2010 using vc++, this program read one input string at a time and produce all anagrams of that string. Input string should include all unique chars not repeated one like "caat" . I have Developed this program using stack and queue data structure. 

This Program will give you basic idea of anagram, you may modify it as per your requirement.

#include
#include
#include
#include

#define MAX 10

using namespace std;

typedef struct
{
char arr[20];
int front;
int rear;
int count;

}Queue;
typedef struct 
{
int top;
char arr[100];
}Stack;
void createQueue(Queue *Q)
{
Q->front=-1;
Q->rear=-1;
Q->count=0;
}
void EnQueue(Queue *Q,char c)
{
if(Q->front==-1 && Q->rear==-1)
{
Q->arr[0]=c;
Q->rear=0;
Q->front=0;
Q->count++;
return;
}
Q->rear=(Q->rear+1)%MAX;
Q->arr[Q->rear]=c;
Q->count++;
}

char DeQueue(Queue *Q)
{
if(Q->count<=0)
{
return '0';
}

char c=Q->arr[Q->front];
Q->front=(Q->front+1)%MAX;
Q->count--;
return c;
}

int isEmpty(Queue *Q)
{
if(Q->count<=0)
return -1;
return 0;
}
char peekQueue(Queue *Q)
{
if(Q->count>0)
return Q->arr[Q->front];
else
return '0';
}
void createStack(Stack *stack)
{
stack->top=-1;
}
void push(Stack *stack,char ele)
{
if(stack->top==-1)
{
stack->arr[0]=ele;
stack->top=0;
}
else
stack->arr[++(stack->top)]=ele;
}
char pop(Stack *stack)
{
if(stack->top==-1) return -1;

return stack->arr[(stack->top)--];

}
float peek(Stack *stack)
{
if(stack->top==-1) return -1;

return stack->arr[stack->top];
}
int isEmpty(Stack *stack)
{
if(stack->top==-1)
return -1;
else
return 0;
}



void main()
{
ifstream ifile;
ifile.open("c:\\prog.txt", ios::in);
//char *input= new char;
string input;

if(ifile)
{
while(!ifile.eof())
{
ifile>>input;
}
}

Stack S;
createStack(&S);

Queue Q;
createQueue(&Q);

int fact=1;
for(int f=input.length();f>0;f--)
{
fact*=f;
}

char pivot;
char c1;
char temp;
int flag=0;
for(int x=0;x
{
for(int i=0;i
{//push all input in stack
push(&S,input[i]);
}

c1=pop(&S);
do
{
EnQueue(&Q,c1);
temp=c1;
if(isEmpty(&S))
{
flag=1;
break;
}
else
c1=pop(&S);
}while(c1>temp);

//if(!isEmpty(&S))
if(flag!=1)
{
pivot=c1;

//step 2:
temp=DeQueue(&Q);
while(temp
{
EnQueue(&Q,temp);
if(isEmpty(&Q))
break;
temp=DeQueue(&Q);
}
push(&S,temp);
EnQueue(&Q,pivot);

//step 3
temp=DeQueue(&Q);
while(temp>pivot)
{
EnQueue(&Q,temp);
if(isEmpty(&Q))
break;
temp=DeQueue(&Q);
}

push(&S,temp);

}//flag

//step 4
while(!isEmpty(&Q))
{
push(&S,DeQueue(&Q));
}

int j=input.length();
while(!isEmpty(&S))
{
input[--j]=pop(&S);
}

cout<<"\n"<
flag=0;

}//for

}


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